8x^2+34x+21=(2x+7)(4x-21)

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Solution for 8x^2+34x+21=(2x+7)(4x-21) equation: 



8x^2+34x+21=(2x+7)(4x-21)

We move all terms to the left:

8x^2+34x+21-((2x+7)(4x-21))=0

We multiply parentheses ..

8x^2-((+8x^2-42x+28x-147))+34x+21=0



We calculate terms in parentheses: -((+8x^2-42x+28x-147)), so:

(+8x^2-42x+28x-147)

We get rid of parentheses

8x^2-42x+28x-147

We add all the numbers together, and all the variables

8x^2-14x-147

Back to the equation:

-(8x^2-14x-147)



We add all the numbers together, and all the variables

8x^2+34x-(8x^2-14x-147)+21=0

We get rid of parentheses

8x^2-8x^2+34x+14x+147+21=0

We add all the numbers together, and all the variables

48x+168=0

We move all terms containing x to the left, all other terms to the right

48x=-168

x=-168/48

x=-3+1/2

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